Minimum Sum of Maximums
Bessie has N (2≤N≤300) tiles in a line with ugliness values a1,a2,…,aN in that order (1≤ai≤106). K (0≤K≤min(N,6)) of the tiles are stuck in place; specifically, those at indices x1,…,xK (1≤x1<x2<⋯<xK≤N).
Bessie wants to minimize the total ugliness of the tiles, which is defined as the sum of the maximum ugliness over every consecutive pair of tiles; that is, ∑i=1N−1max(ai,ai+1). She is allowed to perform the following operation any number of times: choose two tiles, neither of which are stuck in place, and swap them.
Determine the minimum possible total ugliness Bessie can achieve if she performs operations optimally.
Bessie can swap the second and third tiles so that a=[1,10,100], achieving total ugliness max(1,10)+max(10,100)=110. Alternatively, she could swap the first and second tiles so that a=[100,1,10], also achieving total ugliness max(100,1)+max(1,10)=110.
Bessie could swap the first and second tiles so that a=[100,1,10], achieving total ugliness max(100,1)+max(1,10)=110.
The initial total ugliness of the tiles is max(1,100)+max(100,10)=200. Bessie is only allowed to swap the first and third tiles, which does not allow her to reduce the total ugliness.
SCORING:
- Input 5: K=0
- Inputs 6-7: K=1
- Inputs 8-12: N≤50
- Inputs 13-24: No additional constraints
Problem credits: Benjamin Qi
Source: USA Computing Olympiad.
Input Format
The first line contains N and K.
The next line contains a1,…,aN.
The next line contains the K indices x1,…,xK.
Output Format
Output the minimum possible total ugliness.